(x-4)^2-x=5

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Solution for (x-4)^2-x=5 equation: 



(x-4)^2-x=5

We move all terms to the left:

(x-4)^2-x-(5)=0

We add all the numbers together, and all the variables

-1x+(x-4)^2-5=0

We move all terms containing x to the left, all other terms to the right

-1x+(x-4)^2=5

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